Home Free English Pronunciation Tools Use in a sentence / q

Examples of the the word, q , in a Sentence Context

The word ( q ), is the 1646 most frequently used in English word vocabulary

Mastering contextual understanding of words and phrases is a vital skill for effective communication and English learning. Enhance your proficiency by practicing with our handpicked collection of 50 English phrases.

At the end of the list you can practice your english pronunciation

  1. Frac\right)\delta.: c_ q (1) = \mu ( q ). \;: c_ q ( q ) = \phi (, q ,). \;: \sum_do (\delta) = \left (\sum’d (\delta)\right)^2. \; Compare this
  2. P from a to a do for q from 2⌊a to 2⌈a do if abs app, q > y then y: = abs app, q ,; i: p; k: q phi od; y end # abs max # Note: lower (⌊) and upper (⌈)
  3. R is less than the shorter length s. In modern words, remainder r = l − q *s, q ,being the q uotient, or remainder r is the" modulus ", the integer-fractional
  4. I and k; comment begin real y: 0; i: a; k: = 2⌊a; for p from a to a do for, q ,from 2⌊a to 2⌈a do if abs app, q > y then y: = abs app, q ; i: p; k: q phi od; y
  5. The rational function 1/p can be written as the sum of a polynomial function, q ,with rational functions of the form a/ (x − b)n. Therefore, the rational
  6. Only if p (x) has roots. But if q (x) = in + an − 1xn − 1+ ··· + a0,then, q ,(x) is the characteristic polynomial of the companion matrix:
  7. Is ‹ -the ›, hence a" bit" is in Afrikaans and in Dutch. The letters ‹ c ›, ‹, q , ›,‹ x ›, and ‹ z › occur almost exclusively in borrowings from French, English
  8. don't have a common root, for if a ∈ F was a common root, then p (x) and, q ,(x) would both be multiples of x − a, and therefore they would not relatively
  9. Y by z to get a q uotient q and remainder r, there is an outer loop which sets, q ,and r first to the q uotient and remainder of 1/z, then to those of 2/z, and so
  10. And the fraction with the recessive phenotype is q 2. With three alleles:: p +, q ,+ r = 1 \, and: p^2 + 2p q + 2pr + q ^2 + 2 q r + r^2 = 1 \, In the case of
  11. Gamma_ m_ \gamma_ \s q uad \ q uad \text rm \ q uad n 1,2,3,4 \ q uad \text \ q uad, q ,= 1,2,\dots, Q where \gamma_ is generally taken to be the duration of the QC
  12. En# 100&as_subj bio biology,http://scholar.google.co.uk/scholar?, q ,%22Algebraic+Geometry%22&hl en# 100&as_subj chm chemistry
  13. Since p (x) has no roots in F, q (x) also has no roots in F. Therefore, q ,(x) has degree greater than one, since every first degree polynomial has one
  14. Is in fact defined everywhere except at the fixed points. For almost any point, q , on the boundary, ( assuming it is not a fixed point) the one manifold with
  15. Can be e q uated with the mass of the ion’m,via Newton's law (F=ma): ma =, q ,\tabla \phi a = \franc \tabla \phi Relativistic effects in the ion flight are
  16. Pairs. Rules for generating Thābit's rule states that if: p = 3 × 2n − 1 − 1,:, q ,= 3 × 2n − 1,: r = 9 × 22n − 1 − 1,where n > 1 is an integer and p, q ,and r
  17. En# 100&as_subj chm chemistry,http://scholar.google.co.uk/scholar?, q ,%22Algebraic+Geometry%22&hl en# 100&as_subj bus economics
  18. Frac\phi ( q )\\ &=\sum_\mu\left (\franc\right)\delta. \end Note that \phi (, q ,) = \sum_\mu\left (\franc\right)\delta.: c_ q (1) = \mu ( q ). \;: c_ q ( q ) =
  19. En# 100&as_subj bus economics,http://scholar.google.co.uk/scholar?, q ,%22Algebraic+Geometry%22&hl en# 100&as_subj PHY physics and of course other
  20. x. Regarding the division algorithm, when dividing y by z to get a q uotient, q ,and remainder r, there is an outer loop which sets q and r first to the
  21. But ℓ1 and ℓ∞ are not reflexive. When p < ∞, the dual of up is HQ where p and, q ,are related by the formula 1/p + 1/ q = 1. See L p spaces for details.
  22. Q (x) be some irreducible factor of p (x). Since p (x) has no roots in F, q ,(x) also has no roots in F. Therefore, q (x) has degree greater than one
  23. Values of q ),it is an integer. For a fixed value of n it is multiplicative in, q ,:: If q and r are cop rime, c_ q (n)c_r (n)=c_ (n). \; Many of the functions
  24. 0. And to" measure" is to place a shorter measuring length s successively (, q ,times) along longer length l until the remaining portion r is less than the
  25. Of q ),it is an integer. For a fixed value of n it is multiplicative in q :: If, q ,and r are cop rime, c_ q (n)c_r (n)=c_ (n). \; Many of the functions
  26. q ) = \sum_\mu\left (\franc\right)\delta.: c_ q (1) = \mu ( q ). \;: c_ q (, q ,) = \phi ( q ). \;: \sum_do (\delta) = \left (\sum’d (\delta)\right)^2. \;
  27. To y, and the subscripts of this element to i and k; begin integer p, q ,; y: 0; i: k: = 1; for p: =1 step 1 until n do for q : =1 step 1 until m do if
  28. 1 − 1,: q = 3 × 2n − 1,: r = 9 × 22n − 1 − 1,where n > 1 is an integer and p, q , and r are prime numbers, then 2np q and 2nr are a pair of amicable numbers.
  29. N do for q : =1 step 1 until m do if abs (app, q ) > y then begin y: = abs (app, q ,); i: p; k: q end Abs max Here's an example of how to produce a table using
  30. I: k: = 1; for p: =1 step 1 until n do for q : =1 step 1 until m do if abs (app, q ,) > y then begin y: = abs (app, q ); i: p; k: q end Abs max Here's an
  31. 0; i: a; k: = 2⌊a; for p from a to a do for q from 2⌊a to 2⌈a do if abs app, q ,> y then y: = abs app, q ; i: p; k: q phi od; y end # abs max # Note: lower (⌊
  32. Reformed alphabet discarded six letters Franklin regarded as redundant (c, j, q , w, x,and y),and substituted six new letters for sounds he felt lacked
  33. Mentioned above does exist, and the only possibility is that it leads from, q ,to a fixed point. It is an easy numerical task to follow such a path from q to
  34. Polynomial q (x) which has roots if and only if p (x) has roots. But if, q ,(x) = in + an − 1xn − 1+ ··· + a0,then q (x) is the characteristic
  35. It is defined as a sum of complex numbers (irrational for most values of, q ,), it is an integer. For a fixed value of n it is multiplicative in q :: If q
  36. There is some non-constant polynomial p (x) in FX without roots in F. Let, q ,(x) be some irreducible factor of p (x). Since p (x) has no roots in F, q
  37. I and k; begin integer p, q ; y: 0; i: k: = 1; for p: =1 step 1 until n do for, q ,: =1 step 1 until m do if abs (app, q ) > y then begin y: = abs (app, q ); i: p;
  38. Element of FX. Dividing by its leading coefficient, we get another polynomial, q ,(x) which has roots if and only if p (x) has roots. But if q (x) = in +
  39. P, and occurring in that part of the Arabic alphabet (between historic o and, q ,). Esperanto letters with circumflexes, ĉ,ĝ, ĥ,ĵ and ŝ, are written as those
  40. Of more studies on algebraic geometry in http://scholar.google.co.uk/scholar?, q ,%22Algebraic+Geometry%22&hl en# 100&as_subj bio biology
  41. Phy physics and of course other areas of http://scholar.google.co.uk/scholar?, q ,%22Algebraic+Geometry%22&hl en# 100&as_subj ENG mathematics. Austin is the
  42. 2n − 1,: r = (2 (n - m)+1)2 × 2 m + n − 1,where n>m> 0 are integers and p, q , and r are prime numbers, then 2np q and 2nr are a pair of amicable numbers.
  43. A do for q from 2⌊a to 2⌈a do if abs app, q > y then y: = abs app, q ; i: p; k:, q ,phi od; y end # abs max # Note: lower (⌊) and upper (⌈) bounds of an
  44. It will have some root a, which will be then a common root of p (x) and, q ,(x). If F is not algebraically closed, let p (x) be a polynomial whose
  45. Step 1 until m do if abs (app, q ) > y then begin y: = abs (app, q ); i: p; k:, q ,end Abs max Here's an example of how to produce a table using Elliott 803
  46. Prime polynomials and roots For any field F, if two polynomials p (x), q , ( x) ∈ FX are relatively prime then they don't have a common root, for if a ∈
  47. P + q =1 \, : p^2 + 2p q + q ^2=1 \, where p is the fre q uency of one allele and, q ,is the fre q uency of the alternative allele, which necessarily sum to unity.
  48. Of this is Euler's rule, which states that if: p = (2 (n - m)+1) × 2 m − 1,:, q ,= (2 (n - m)+1) × 2n − 1,: r = (2 (n - m)+1)2 × 2 m + n − 1,where n>m> 0
  49. Note that \phi ( q ) = \sum_\mu\left (\franc\right)\delta.: c_ q (1) = \mu (, q ,). \;: c_ q ( q ) = \phi ( q ). \;: \sum_do (\delta) = \left (\sum’d (
  50. Closed fields. If the field F is algebraically closed, let p (x) and, q ,(x) two polynomials which are not relatively prime and let r (x) be their

Now it is your turn - use the english voice checker

Take control of your English pronunciation with our Voice Checker tool. It's your turn to sound confident and fluent!


Here it will appear the recognized speech.

Your voice recordings list

To download your recording the the download link above the audio player

Our data base is updated daily, click here to check out all sentences

Free Text to Speech Tool: Convert Text to Audio Online

Now that you have trained speaking all the phrases you can use our tool to improve your english speaking skills. You have the option of using four different synthesized english voices: Microsoft Mark - English (United States), Microsoft Zira - English (United States), Microsoft David - English (United States), Google US English, Google UK English Female, Google UK English Male

Note that it may take some seconds for your to be able to hear the voice