Examples of the the word, ord , in a Sentence Context
The word ( ord ), is the 13642 most frequently used in English word vocabulary
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- check ISIN (value): value = value. Strip (). Upper () char map = dict (( i, ord , ( i)-55) for i in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' + (i, int (i) ) for i in
- Ord (f (a) ) divides ORD (a). If f is injective, then ORD (f (a) ) =, ord , ( a). This can often be used to prove that there are no (injective)
- Of group G is 1,then the group is called a trivial group. Given an element a, ord , ( a) 1 if and only if an is the identity. If every (non-identity) element in
- Ƒg' + ƒ'g. Property (iii): any ƒ can be written in the form ƒ km g, with m, ord , ( ƒ) and ORD (g) 0: then ƒ'/ƒ MX −1 + g'/g. Since ORD (g) 0,the element g
- Langle a \range). For any integer k, we have: AK = e if and only if, ord , ( a) divides k. In general, the ord er of any subgroup of G divides the ord er
- Series, the minimal integer n such that an≠0 is called the ord er of f, denoted,ORD, ( f). (The ord er of the zero series is +∞. ) The formal Laurent series form
- Or likely perpetrators. Bibliography * Rear, mulla (2004). Med gene, ord , ( " In My Own W ord s" ). Autobiography. Oslo: Aschehoug. 246 pp. ISBN
- Found a large stone slab on which was carved a cross with the inscription, ord , do degen. This refers to Bishop Degen, who lived in Ireland during the 7th
- Input_ch ==" ": break random_ch = PNG. Next_byte () & 0xff g. write (CHR (, ord , ( input_ch) ^ random_ch) ) f. close () g. close () main () The C code is
- Flatten left Legend ORD 2006 after an internal conflict. In 2009,Legend, ord , changed its name to Credokirken (The Credo Church). Credo is Latin for" I
- Of G divides the ord er of G. More precisely: if H is a subgroup of G, then:, ord , ( G) / ORD (H) = G: H, where G: H is the index of H in G, an integer. This
- 4: begin t: t - 1; st: st 5: begin t: t - 1; st: st div st + 1 end; 6: st: =, ord , ( odd (st) ); 8: begin t: t - 1; st: ORD (st = st + 1) end; 9: begin t: t -
- Finite ord er, then ORD (f (a) ) divides ORD (a). If f is injective, then,ORD, ( f (a) ) = ORD (a). This can often be used to prove that there are noes (
- The ord er of G. More precisely: if H is a subgroup of G, then: ORD (G) /, ord , ( H) = G: H, where G: H is the index of H in G, an integer. This is Lagrange
- Not exp logs rand xor sqq ex xor s x x length UC ORD and print CHR, ord , for QC q join use sub tied ex xor evil xor print HQ q xor int evil LC q m cos
- Has finite ord er. If ab = BA, we can at least say that ORD (ab) divides LCM (, ord , ( a),ORD (b) ). As a consequence, one can prove that in a finite Abelian
- Of finite groups have finite ord er. The ord er of a group G is denoted by, ord , ( G) or | G | and the ord er of an element an is denoted by ORD (a) or | a |.
- End; 10: begin t: t - 1; st: ORD (st < st + 1) end; 11: begin t: t - 1; st:, ord , ( st >= st + 1) end; 12: begin t: t - 1; st: ORD (st > st + 1) end; 13:
- Use sub tied ex xor evil xor print HQ q xor int evil LC q m cos and print CHR, ord , for QC y abs né open tied hex exp ref y m xor scalars rand print HQ q xor int
- S3 has the following multiplication table.: This group has six elements, so,ORD, ( S3) 6. By definition, the ord er of the identity, e,is 1. Each of s’t,and
- G is denoted by ORD (G) or | G | and the ord er of an element an is denoted by, ord , ( a) or | a |. Example. The symmetric group S3 has the following
- St) ); 8: begin t: t - 1; st: ORD (st = st + 1) end; 9: begin t: t - 1; st:, ord , ( st <> st + 1) end; 10: begin t: t - 1; st: ORD (st < st + 1) end; 11:
- Formula for the ord er of the powers of a:: ORD (AK) = ORD (a) / CD (, ord , ( a),k) for every integer k. In particular, a and its inverse a−1 have the
- Non-identity) element in G is the same as its inverse (so that a2 e),then, ord , ( a) 2 and consequently G is Abelian since ab (ab)^ bad BA by Elementary
- The ord er of the group. For example, in the symmetric group shown above, where,ORD, ( S3) = 6,the ord ers of the elements are 1,2,or 3. The following partial
- Finite ord er, we have the following formula for the ord er of the powers of a::, ord , ( AK) = ORD (a) / CD (ORD (a),k) for every integer k. In particular, a
- And true. For conversion to integer, ord is used: i: =, ord , ( b); There is no standard function for integer to boolean, however,the
- X y or print HQ s and evil q s under or Oct xor time xor ref print CHR int, ord , lc for each QC y hex alarm chair kill exec return y s gt sin sort split Using
- Professor of Climatology UK # Prof. Dr. Władysław Dobrzaniecki, head of the, ord , Odd. Chirurgii PSP # Prof. Dr. Jan Grew, Professor of Internal Medicine, UJK
- Property (iii): any ƒ can be written in the form ƒ km g, with m ORD (ƒ) and, ord , ( g) 0: then ƒ'/ƒ MX −1 + g'/g. Since ORD (g) 0,the element g is invertible
- Theorem include: the ord er of a group G is a power of a prime p if and only if, ord , ( a) is some power of p for every an in G. If a has infinite ord er, then all
- Not exp logs rand xor sqq ex xor s x x length UC, ord , and print CHR ORD for QC q join use sub tied ex xor evil xor print HQ q xor
- Ludwig Rune berg): Part land, vårt land, vårt foster land, : loud host, o Dora, ord , !: Ex lifts en hold mot him lens rand, : ex banks en DAL, ej skills en strand,
- And an is an element of G of finite ord er, then ORD (f (a) ) divides, ord , ( a). If f is injective, then ORD (f (a) ) = ORD (a). This can often be
- We have the following formula for the ord er of the powers of a:: ORD (AK) =, ord , ( a) / CD (ORD (a),k) for every integer k. In particular, a and its
- Y m xor scalars rand print HQ q xor int evil LC HQ y sort cos and print CHR, ord , for QC x print each return local x y or print HQ s and evil q s under or Oct
- 1; st: st div st + 1 end; 6: st: = ORD (odd (st) ); 8: begin t: t - 1; st:, ord , ( st = st + 1) end; 9: begin t: t - 1; st: ORD (st <> st + 1) end; 10: begin
- If f: G → H is a homomorphism, and an is an element of G of finite ord er, then,ORD, ( f (a) ) divides ORD (a). If f is injective, then ORD (f (a) ) = ORD (
- The possible values of boolean are false and true. For conversion to integer, ord , is used: i: = ORD (b); There is no standard function
- End; 12: begin t: t - 1; st: ORD (st > st + 1) end; 13: begin t: t - 1; st:, ord , ( st ← st + 1) end; end; LOD: begin t: t + 1; st: base (l) + an end; STO:
- In Sweden and Norway. The allegations in the Swedish Nazi magazine Aria, ord , ( " Free W ord s" ) in 1957 came from the Danish author and critic Harald
- Infinite ord er while ab has finite ord er. If ab = BA, we can at least say that, ord , ( ab) divides LCM (ORD (a),ORD (b) ). As a consequence, one can prove
- Form ƒ km g, with m ORD (ƒ) and ORD (g) 0: then ƒ'/ƒ MX −1 + g'/g. Since, ord , ( g) 0,the element g is invertible in KM ⊂ I'm (D) KER (Res),whence Res (
- End; 11: begin t: t - 1; st: ORD (st >= st + 1) end; 12: begin t: t - 1; st:, ord , ( st > st + 1) end; 13: begin t: t - 1; st: ORD (st ← st + 1) end; end; LOD
- Old. This holy temple has three holy idols of L ord Dinah, L ord Nominate and, ord , Mahaveera and 21 other" Theerthankaras ". It is very recently renovated by
- Palace was called Erdman Dalai Bryan Chilean sum or Bond Shaanxi sermon, ord , Other palaces were the White palace (Sagan sum or NCAA deciding),and
- Set in use, and vice versa. e.g. on systems using the ASCII character set, ord , ( '1' ) = 49 and CHR (9) is a TAB character. Boolean types In Pascal
- Characters and integers are distinct types. The inbuilt compiler functions, ord , ( ) and CHR () can be used to typecast single characters to the corresponding
- Order. If ab = BA, we can at least say that ORD (ab) divides LCM (ORD (a),ORD, ( b) ). As a consequence, one can prove that in a finite Abelian group, if m
- End; 9: begin t: t - 1; st: ORD (st <> st + 1) end; 10: begin t: t - 1; st:, ord , ( st < st + 1) end; 11: begin t: t - 1; st: ORD (st >= st + 1) end; 12:
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